This is not one of the classic Microsoft puzzle. I recently heard from a friend. I am listing the problem below.
Question:
There is a table on which a number of coins are placed. You also know that there are as many coins with Head up as many coins with Tail up. Now you have to divide the coins (number of coins is even)
into two equal piles such that number of coins with Heads up and Tails up in either piles be the same. The catch is you are blind folded and you cannot determine the sides (for sure) if you are blinded
POST YOUR OPINION IF YOU HAVE BETTER SOLUTION
1 comment
After you split the coins into two equal piles, flip all the coins in one of the piles.
Ex:
100 coins with 50 heads and 50 tails
Random split:
Pile 1 - 40 heads 10 tails
Pile 2 - 10 heads and 40 tails
You can flip all the coins in pile 1 and get 10 heads and 40 tails in both piles, or flip the coins in pile 2 and get 40 heads and 10 tails in both piles.
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